That calculator is based on ICE car data.Yeah, not legally on public roads, at least in the USA. The SpaceX collab. could also be in materials science, not just propulsion. 4 plaid motors are already capable of 2,000 hp (Tesla Semi w. 3 can be custom-configured for each customer w. up to 1,500 hp).
Assuming that maintaining traction limits front wheel power to half of the each rear wheel, that's 1,500 hp to the ground. This 0-60 mph calculator says a car w. 1,500 hp will go 0-60 mph in less than a second if it weighs 2,150 lbs. So it's either they've given up the 600 mi range and gone to a light weight battery pack, or its some form of traction aide (aerodynamic, or reaction-mass).
If traction ISN'T the limiting factor, and all 2,000 hp can be used, then the car could weigh up to 2,900 lbs. A more reasonable 4,000 lb car would need 2,755 hp which means what, 6 motors?! WTF, nutty combos from here on up. Superconductors? I'm boggled at this point...
So either the battery is lighter, or the only obvious remaining solution:
...ALIEN ANTI-GRAVITY TECHNOLOGY.
Cheers to the Crazy Ones!
P.S. This 1/4 Mile ET-MPH-HP Calculator says a 2,900 lb car with 2,000 hp can do this:
Your ET / MPH computed from your vehicle weight of 2900 pounds andHP of 2000is 6.59 seconds and MPH of 204.98 MPH.
I just hope they give it enough bty pack capacity to do a full lap of the Nürburgring.
From a pure physics point of view (in a vacuum):
If the motors can put 1500 hp to the ground at 60 MPH, let that be the max traction of the tires, and also the max force (constant torque from 0 (which is 0 hp)).
1500hp=1118.55kW=kJ/s=kNm/s
60mph=26.8m/s
1118.55/26.8 = 41.75 kN
f=ma
41.75kN=m*26.8m/s²
m=1.56kkg=3,426 pound car
Verification:
Ke=0.5*1560kg*(26.8m/s)²=560kJ
In one second: 560kJ/s
Assuming constant acceleration and linear power increase:
Power at end: 2*560kJ/s=1120kW
Yep, that matches
Of course, this requires tires with a coefficient of friction of 26.8/9.8 = 2.7, with no rolling resistance...