ItsNotAboutTheMoney
Well-Known Member
You aren't using an harmonic mean. Range is proportional to mpge, but average has to be an harmonic mean.No,
Highway is weighted 45% and city 55% so we can calculate exactly what highway EPA range is with the 128 city, 110 highway and 119 average.
.55city + .45highway = 238miles
Highway = 110/128*city
City = 128/110*highway
Solving the above system:
Highway Range = 218miles
City Range = 254miles
Good numbers, Chevy should be proud of them, the Bolt is clearly the best non-Tesla EV and the best EV under 40K. But to me, highway range is much more important than city, and I often exceed 90mph when passing, still waiting for M3.
Edit: in the above post ItsNotAboutTheMoney didn't weight the numbers in his last calculation which is why they are slightly off.
Extreme example: say it has 60kWh available and uses 0.06kWh per mile city, and 60kWh/mile highway.
Then city range is 1000 miles and highway range is 1 mile.
According to your calculation, overall range is 0.55x1000+0.45×1=551.
However, imagine the car travels 1 mile, 0.55 city and 0.45 highway. How much energy would it use?
0.55 x 0.06 + 0.45 × 60 = 0.033 + 27 = 27.033kWh. That is, in 1 mile it'd have almost used half the battery, so its range must be a bit over 2 miles.
The harmonic mean takes care of the problem by inverting the distance/unit consumption to give consumption/unit distance, which you weight to give overalll consumption/unit distance, and then invert to give the overall distance per unit consumption. If assuming range simply proportional to mpge (its actualky based on exhaustion in repeated cycles), then in your system of equations you need:
0.55/city+0.45/highway =1/238.
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