Wiki states:
My question is: since SOC is so significant to charge times does the car somehow manage to deplete each of the group that are wired in parallel before then starting to use another? If it did this then a battery with say 50% charge would actually consist of 47 groups at 100% and 47 groups at 0%.
Can anyone tell me if this is indeed what happens, or if not why not. I suspect that the answer is going to be "no"...but I can't immediately see why this approach of depleting one group at a time would not work (and it would clearly improve charge times if it could be done).
Thanks
Andrew
The 85 kWh battery pack weighs 1,200 lb (540 kg)[102][better source needed] and contains 7,104 lithium-ion battery cells in 16 modules[103] wired in series (14 in the flat section and two stacked on the front). Each module contains 6 groups of 74 cells[105] wired in parallel; the 6 groups are then wired in series within the module
Being Lithium Ion each cell is going to be about 3.6 volts... each module has 6 groups so 6 x 3.6v and then there are 16 modules in series so the total would be 16 x 6 x 3.6 = 345v. Can anyone confirm this?
My question is: since SOC is so significant to charge times does the car somehow manage to deplete each of the group that are wired in parallel before then starting to use another? If it did this then a battery with say 50% charge would actually consist of 47 groups at 100% and 47 groups at 0%.
Can anyone tell me if this is indeed what happens, or if not why not. I suspect that the answer is going to be "no"...but I can't immediately see why this approach of depleting one group at a time would not work (and it would clearly improve charge times if it could be done).
Thanks
Andrew