Cottonwood
Roadster#433, Model S#S37
The only way to reduce line losses is to put in bigger wires.
Your wires have the same resistance regardless of the current so 20 amps for 10 hours will give you the same loss as 40 amps for 5 hours (unless you are overheating the wires which is a different problem).
So, if you have properly sized wiring (or better still, oversize wiring) there's no need to reduce current. Your line loss will be the same.
Actually, not true.
The power dissipation in the wires is I^2*R, the current squared times the resistance. You are correct that the resistance can be reduced with bigger wire, but for any given wire size, the power lost to the wire's resistance falls as the square of the current reduction. The time to charge goes up linearly, so the total power lost in the wire for a given amount of charging and other resistive losses falls linearly with the current. As you get to very low charge rates, there are other overheads and inefficiencies that dominate, but the resistive losses continue to fall with current.