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your right - electron has not been filled, just moved.
E = mc^2
m = E / c^2
1 [kwh] = 3.6x10^6 [J]
c = 300.000.000 [m/s]
1 Tesla charge [Tesla*] = 85 [kwh]
1 [kg] = 1 [J] / (1 [m^2]/ 1 [s^2])
m [kg] = (85 [kwh/Tesla*] * 3.6x10^6 [J/kwh])/300.000.000 ^2 [m/s]
m [kg] = 3.06x10^8 [J/Tesla*] / 9x10^16 [m^2/s^2]
m [kg] = 0.34x10^-8 [J/Tesla*] / [m^2/s^2]
m [kg] = 0.34x10^-8 [kg/Tesla*]
m = 0.0034 [mg/Tesla*]
3.4 microgram
My P85 on the scales.... 4,690....
Extra credit to Niels for showing his work.
That is all good and peachy but those electrons just move to the other side of the battery. You need to use E=MC^2 to determine the mass differential. We did it before I'll look for the link.
or you can just put 85kWh into WolframAlpha
85kWh in g - Wolfram|Alpha
Ends up being 0.000003405 grams! So not grams but mircograms.
your right - electron has not been filled, just moved.
E = mc^2
m = E / c^2
1 [kwh] = 3.6x10^6 [J]
c = 300.000.000 [m/s]
1 Tesla charge [Tesla*] = 85 [kwh]
1 [kg] = 1 [J] / (1 [m^2]/ 1 [s^2])
m [kg] = (85 [kwh/Tesla*] * 3.6x10^6 [J/kwh])/300.000.000 ^2 [m/s]
m [kg] = 3.06x10^8 [J/Tesla*] / 9x10^16 [m^2/s^2]
m [kg] = 0.34x10^-8 [J/Tesla*] / [m^2/s^2]
m [kg] = 0.34x10^-8 [kg/Tesla*]
m = 0.0034 [mg/Tesla*]
3.4 microgram
I'm pretty impressed how many people on this board know enough science to answer this question correctly. Very different than the previous car club I was a part of!
I'm really curious how people on other EV forums would do with this question. Is anyone willing to post a similar question on the Chevy Volt forum, the Nissan LEAF forum, the Fisker Karma forum, etc. and report the results? (you would obviously change the name of the EV to match the forum)