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Practical Conclusions About Vehicle Speed When Less than Winter Tyres are Used

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SageBrush

REJECT Fascism
May 7, 2015
14,862
21,485
New Mexico
Disclaimer: my conclusions are calculations based on my application of presumed simple newtonian mechanics. Since my ability to even pass an O level physics exam without some review is uncertain, I welcome critical review and corrections as appropriate.

Phew ! On to the story ...

I watched a very nice winter driving test done by TFL. In it they measured the time it takes to go from 0 to 25 mph, and stopping distances. Two AS tyres, an all-weather tyre, and the Blizzak were tested. To flesh out their results, I presumed that tyre friction to accelerate is the same as deceleration. This graph was the result

Screen Shot 2022-12-29 at 8.29.28 AM.png

Then I wondered how much slower a car speed has to be to stop in the same distance as one with Blizzaks. I calculate it as (1 / sqrt of the acceleration time ratio). So e.g if comparing the AS #1 (9.8 sec) with the Blizzaks (6.85 sec), the AS tyred vehicle has to travel at 1 / sqrt(9.8/6.85) = 84% of the speed of the Blizzaked vehicle. A vehicle with All-weather has to travel at 96% the relative speed


YouTube Video Data. Stopping distance of the AS #1 (Michelin Primacy) is calculated
Add some more if you like ! I've had enough arithmetic for one day, but I think it would interesting to calculate reasonable winter driving speeds compared to posted speed limits (used in the summer) and following distances.
 
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